Net603
Currently we are going over binary and how it related to both the Ip address and subnet mask assigned to computers.
As we can see in the picture illustrated above our IP address has two ways in which it can be viwed;the series of numbers we see when we look at the IP address when we look at our ipconfig (on windows) or ifconfig(Ubunto) such as 145.10.34.3(pictured above) This presentation of our IP address is so that humans can read the series of numbers much easier than if they were displayed the same way the computer reads the Ip address- a series of 8bit binary numbers which are 0's and 1's.
Each Octet can hold up to 255 which can hold a wide range of numbers. If we had a look at the picture above we can note that the first three Octets from the left represent the network while the last Octet is left alone to be assigned to the users/hosts who join the network.
Warren Lourens
Blog Entry - NET603
WHAT
Learning outcomes relate to converting decimal into binary, specifically with regards to sub-netting.
A Subnet Mask allows us to determine where within the IP address the network ends and the host, or client begins. The IP address is a set of decimal numbers that represent a conversion of a 32 bit binary number.
The 32 bit binary number is split into 4 octets each containing 8 of the 24 bits. Each bit represents either a 0 or 1, or to put it another way 'On' or 'Off'.
WHY
We normally interact between networks using IP addresses which are represented as 4 octets, for example 192.168.1.1. An IP address however is not a real interpretation of what the computer understands, it is merely a representation that allows us to quickly and efficiently work with network systems.
In order to understand what is happening in real terms, that the computer understands, we have to convert the IP address into binary.
HOW
We need to covert each octet into binary, so in the above example we have 192.168.1.1. The decimal numbers to allow conversion always start on the right and begin with a 1, then double all the way up to 128:
So if we take the 192 we ask ourselves, does 128 fit into 192? The answer is yes so that is represented by a 1 in binary. Then we move onto the next number in the sequence and ask ourselves, does 64 fit into 192 after the 128 has been allocated to it? The answer is yes so that gets a 1 also. Those two numbers make the total 192 so the rest of the 6 digits are represented by a 0 leaving us with the 8 bit sequence of 0s and 1s.
So now how do we determine the Subnet Mask?
If we take an example network range of 192.168.1.0 > 192.168.1.255 where the first three octets represent the network and the last one represents the hos,t we have a total of 256 IP address, with 254 reserved for hosts machines. The reason there are 256 addresses is because we have a range between 0 and 255, so 255 + 0 = 256. The reason we have 254 hosts is because the first IP address, 192.168.1.0 is reserved for the network address, and the last 192.168.255.255 is reserved for the broadcast address.
So in the above example IP range we have a subnet mask of 255.255.255.0.
So because the decimals, when added together equal 255, means that converting the decimal to binary in this instance is simple, but how do we know where the network ends and the host begins?
This 'point' that distinguishes the network and the host is between the last 1, and the first 0. So the binary shows us that 255.255.255 represents the network, and the .0 represents the host or client machine/printer etc..
The subnet mask can be anywhere along the 32 bits, it operates in a sliding scale. So we can take a subnet mask of 255.255.240.0 which in binary is 11111111.11111111.11110000.00000000. This shows the network ending 4 bits into the third octet, or 20 bits into the binary in total.
This can be represented in the IP address by adding the '1' bit numbers representing the network to the end of the IP address as /20, because there are 20 '1s' in the bit sequence, for example 125.238.219.173 /20.
Dale Stephenson
Submitted 28.02.20 16.54
Warren Lourens
Blog Entry - NET603
WHAT
Learning outcomes relate to converting decimal into binary, specifically with regards to sub-netting.
A Subnet Mask allows us to determine where within the IP address the network ends and the host, or client begins. The IP address is a set of decimal numbers that represent a conversion of a 32 bit binary number.
The 32 bit binary number is split into 4 octets each containing 8 of the 24 bits. Each bit represents either a 0 or 1, or to put it another way 'On' or 'Off'.
WHY
We normally interact between networks using IP addresses which are represented as 4 octets, for example 192.168.1.1. An IP address however is not a real interpretation of what the computer understands, it is merely a representation that allows us to quickly and efficiently work with network systems.
In order to understand what is happening in real terms, that the computer understands, we have to convert the IP address into binary.
HOW
We need to covert each octet into binary, so in the above example we have 192.168.1.1. The decimal numbers to allow conversion always start on the right and begin with a 1, then double all the way up to 128:
| 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1 | ||||||
| 192 | 168 | 1 | 1 | ||||||||||
| 11000000 | 10101000 | 00000001 | 00000001 | ||||||||||
So if we take the 192 we ask ourselves, does 128 fit into 192? The answer is yes so that is represented by a 1 in binary. Then we move onto the next number in the sequence and ask ourselves, does 64 fit into 192 after the 128 has been allocated to it? The answer is yes so that gets a 1 also. Those two numbers make the total 192 so the rest of the 6 digits are represented by a 0 leaving us with the 8 bit sequence of 0s and 1s.
So now how do we determine the Subnet Mask?
If we take an example network range of 192.168.1.0 > 192.168.1.255 where the first three octets represent the network and the last one represents the hos,t we have a total of 256 IP address, with 254 reserved for hosts machines. The reason there are 256 addresses is because we have a range between 0 and 255, so 255 + 0 = 256. The reason we have 254 hosts is because the first IP address, 192.168.1.0 is reserved for the network address, and the last 192.168.255.255 is reserved for the broadcast address.
So in the above example IP range we have a subnet mask of 255.255.255.0.
| 128 + | 64 + | 32 + | 16 + | 8 + | 4 + | 2 + | 1 | = 255 |
| 255 | 255 | 255 | 0 | ||||
| 11111111 | 11111111 | 11111111 | 00000000 |
So because the decimals, when added together equal 255, means that converting the decimal to binary in this instance is simple, but how do we know where the network ends and the host begins?
This 'point' that distinguishes the network and the host is between the last 1, and the first 0. So the binary shows us that 255.255.255 represents the network, and the .0 represents the host or client machine/printer etc..
The subnet mask can be anywhere along the 32 bits, it operates in a sliding scale. So we can take a subnet mask of 255.255.240.0 which in binary is 11111111.11111111.11110000.00000000. This shows the network ending 4 bits into the third octet, or 20 bits into the binary in total.
This can be represented in the IP address by adding the '1' bit numbers representing the network to the end of the IP address as /20, because there are 20 '1s' in the bit sequence, for example 125.238.219.173 /20.
Dale Stephenson
Submitted 28.02.20 16.54
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